0.07/0.12	% Problem    : SLH0134^1 : TPTP v8.2.0. Released v8.2.0.
0.07/0.12	% Command    : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
0.12/0.33	Computer   : n011.cluster.edu
0.12/0.33	Model      : x86_64 x86_64
0.12/0.33	CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
0.12/0.33	RAMPerCPU  : 8042.1875MB
0.12/0.33	OS         : Linux 3.10.0-693.el7.x86_64
0.12/0.33	% CPULimit   : 30
0.12/0.33	% DateTime   : Mon Jul  3 03:37:54 EDT 2023
0.12/0.33	% CPUTime    : 
5.89/6.09	% SZS status Theorem
5.89/6.09	% Mode: mode507:USE_SINE=true:SINE_TOLERANCE=3.0:SINE_GENERALITY_THRESHOLD=0:SINE_RANK_LIMIT=1.:SINE_DEPTH=1
5.89/6.09	% Inferences: 317
5.89/6.09	% SZS output start Proof
5.89/6.09	thf(ty_int, type, int : $tType).
5.89/6.09	thf(ty_num, type, num : $tType).
5.89/6.09	thf(ty_real, type, real : $tType).
5.89/6.09	thf(ty_log, type, log : (real>real>real)).
5.89/6.09	thf(ty_abs_abs_real, type, abs_abs_real : (real>real)).
5.89/6.09	thf(ty_archim6058952711729229775r_real, type, archim6058952711729229775r_real : (real>int)).
5.89/6.09	thf(ty_n, type, n : int).
5.89/6.09	thf(ty_ord_less_eq_real, type, ord_less_eq_real : (real>real>$o)).
5.89/6.09	thf(ty_bit0, type, bit0 : (num>num)).
5.89/6.09	thf(ty_one, type, one : num).
5.89/6.09	thf(ty_numeral_numeral_real, type, numeral_numeral_real : (num>real)).
5.89/6.09	thf(ty_ring_1_of_int_real, type, ring_1_of_int_real : (int>real)).
5.89/6.09	thf(sP1,plain,sP1 <=> ((ord_less_eq_real @ (ring_1_of_int_real @ (archim6058952711729229775r_real @ ((log @ (numeral_numeral_real @ (bit0 @ one))) @ (abs_abs_real @ (ring_1_of_int_real @ n)))))) @ ((log @ (numeral_numeral_real @ (bit0 @ one))) @ (abs_abs_real @ (ring_1_of_int_real @ n)))),introduced(definition,[new_symbols(definition,[sP1])])).
5.89/6.09	thf(sP2,plain,sP2 <=> (![X1:real]:((ord_less_eq_real @ (ring_1_of_int_real @ (archim6058952711729229775r_real @ X1))) @ X1)),introduced(definition,[new_symbols(definition,[sP2])])).
5.89/6.09	thf(conj_0,conjecture,sP1).
5.89/6.09	thf(h0,negated_conjecture,(~(sP1)),inference(assume_negation,[status(cth)],[conj_0])).
5.89/6.09	thf(1,plain,(~(sP2) | sP1),inference(all_rule,[status(thm)],[])).
5.89/6.09	thf(fact_0_of__int__floor__le,axiom,sP2).
5.89/6.09	thf(2,plain,$false,inference(prop_unsat,[status(thm),assumptions([h0])],[1,h0,fact_0_of__int__floor__le])).
5.89/6.09	thf(0,theorem,sP1,inference(contra,[status(thm),contra(discharge,[h0])],[2,h0])).
5.89/6.09	% SZS output end Proof
5.89/6.09	EOF